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Simplifying 2c2 + -5 = 9c Reorder the terms: -5 + 2c2 = 9c Solving -5 + 2c2 = 9c Solving for variable 'c'. Reorder the terms: -5 + -9c + 2c2 = 9c + -9c Combine like terms: 9c + -9c = 0 -5 + -9c + 2c2 = 0 Factor a trinomial. (-1 + -2c)(5 + -1c) = 0Subproblem 1
Set the factor '(-1 + -2c)' equal to zero and attempt to solve: Simplifying -1 + -2c = 0 Solving -1 + -2c = 0 Move all terms containing c to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -2c = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -2c = 0 + 1 -2c = 0 + 1 Combine like terms: 0 + 1 = 1 -2c = 1 Divide each side by '-2'. c = -0.5 Simplifying c = -0.5Subproblem 2
Set the factor '(5 + -1c)' equal to zero and attempt to solve: Simplifying 5 + -1c = 0 Solving 5 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1c = 0 + -5 -1c = 0 + -5 Combine like terms: 0 + -5 = -5 -1c = -5 Divide each side by '-1'. c = 5 Simplifying c = 5Solution
c = {-0.5, 5}
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